I love miniature cars. But they are a bit expensive. I have about 50 bburagos, but it cost me lots of money. Just a question about the evo. Did you also try the Subaru? Just to know, because here in Portugal nobody has an Evo. Not even the cops! They have Imprezas. No idea why, cuz I love the Evo from day one!
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yes torque is force*distance(that's what the Lever Arm is) that's why ALL Torque Wrenches are exactly 1 foot long hence Torque is in Lbs per feet, foot pounds of torque get it?
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next time do your homework, or know what the fuck u're talking about before you post! :roll: and to think that your dad has all those muscle cars and u don't know what a torque wrench looks like?! do u have any pix of your so called dad's cars? or are you just another Donny? :twisted: |
OK dick shit the Camshaft has nothing to do with the stroke of an engine that is the Crankshaft and Actually the equation is just Force*Distance so on those 2 matters you can kneel down and open wide and when I said all torque wrenches are 1 foot long I meant standard torque wrenches yes you can get longer ones but they will be really expensive and not too many things on a car go over about 160. actually more torque is created because of the longer Crankshaft that's why diesel's (the kings of torque) use long blocks not short blocks so once again kneel down bitch. And I went and looked in our garage and yes we do have a 2 foot torque wrench. so it was a slight typo.
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in all my physics classes I've taken (3) and all the automotive books I have (3 textbooks) I was always taught just Force*Distance even though on a rotational basis was always stressed the equation was always just normal distance.
AND: if some dumbass takes a torque wrench and tries to push down on it to turn the bolt they shouldn't even be allowed to ride in a car. |
as its been explained already, Force*Distance/Time= power aka torque. what i think hasnt been adiquately explained is how hp is derived from torque
Horsepower = (trorque)(RPM)/5252 as the power is given in rotational form, it is converted back to liniar form when say, you go down the streatch of tarmac the engine power is lost by By accelerating the car over a distance in a given amount of time. Aerodynamic drag on the vehicle. Rolling friction loss. Some of the energy is dissipated as heat in the gears, torque converter, wheel bearing, and tires. Inertial losses. It takes energy to speed up a mass. Internal components in the vehicle drivetrain that undergo acceleration draw energy. These components include the pistons/connecting rods changing direction, pulleys, flywheel, transmission shafts, drive shaft, axles, and wheels. The mass of the pistons/connecting rods and valves/springs are always a draw on horsepower. The mass of the rotating components only draw horsepower when the engine increases RPM. Lightening up all of these components will reduce inertial losses, and make the engine less stable. On the plus side, these inertial components, once up to speed, will make your car coast further and can help mileage on the highway. But they hither acceleration so buy aluminum or magnesium rims. =P so in retrospect, hp is little more then a differnece between torque and rpm. when looking to buy your next sportscar, look up its torque curve... the flatter the curve, the more linear your accelleration will be, but it wont be a sudden boost of power, but a constant application. some people dont like this, and choose to buy high reving, low torque cars... tho they make decent torque, there is little startoff accelleration (do you really want to try and dump the clutch from 7000 rpms in an S2000?) my 2 cents |
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jeez deth/zevlov lol calm down, we are here to have fun and learn.... so what if we are sometimes wrong...
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where are the pix of your and your dad's cars? |
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yes but in the equation it always just said distance that's what I meant by normal distance.
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Care to list the textbooks you've got, and what classes you've taken? I am a physics major, and I've taken several University of Michigan Engineering school classes on mechanics in addition to my studies in physics. YOU ARE WRONG. The equation for Torque is force times the perpendicular distance to the axis of motion. That means in a simple case...say a wheel...the perpendicular distance to the point of application of the force...i.e. static friction on the road... would be the same distance as the radius of the wheel. In other cases it does not work out that way. If you want to find the torque on a dipole (something that has a positive electric charge at one end, and a negative one at the other end) in a constant electric field, the sum of the forces on the dipole comes to ZERO, but there is still torque, i.e. the thing will still rotate about its center. The torque is measured at a PERPENDICULAR distance to the center of rotation, from both ends separately. The equation for torque is T = R X F where "X" means "cross product" and the force "F" must be applied at a perpendicular to the lever arm "R". If you would like a more thorough explanation of what torque is, and how to find it, I will be more than happy to look it up in any of my 7 physics textbooks, 3 engineering texts, or even some of my high-level math texts. P.S. "Normal" is another word for "perpendicular" |
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